(x^2-25)/(x^2+5x-50)

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Solution for (x^2-25)/(x^2+5x-50) equation: 


D( x )

x^2+5*x-50 = 0

x^2+5*x-50 = 0

x^2+5*x-50 = 0

x^2+5*x-50 = 0

DELTA = 5^2-(-50*1*4)

DELTA = 225

DELTA > 0

x = (225^(1/2)-5)/(1*2) or x = (-225^(1/2)-5)/(1*2)

x = 5 or x = -10

x in (-oo:-10) U (-10:5) U (5:+oo)

(x^2-25)/(x^2+5*x-50) = 0

x^2+5*x-50 = 0

x^2+5*x-50 = 0

DELTA = 5^2-(-50*1*4)

DELTA = 225

DELTA > 0

x = (225^(1/2)-5)/(1*2) or x = (-225^(1/2)-5)/(1*2)

x = 5 or x = -10

(x+10)*(x-5) = 0

(x^2-25)/((x+10)*(x-5)) = 0

1*x^2 = 25 // : 1

x^2 = 25

x^2 = 25 // ^ 1/2

abs(x) = 5

x = 5 or x = -5

x in { 5} 

x = -5

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